A tangent is drawn from a point that is at a distance of 37 cm from center of the circle O, and diameter is 24 cm. The length (in cm) of the tangent is:

Correct option is B

Given:

PQ is a tangent
OP=37cm
Diameter of circle =24cm
Formula Used:
Pythagoras’ Theorem
​$$(H)^2 = (P)^2 + (B)^2$$​​
Where H,P,B are hypotenuse, perpendicular and base respectively of a triangle
Solution:
$$OQ=\frac{ 24}{2 }$$​= 12cm (radius of circle)
OQ⊥ QP ( radius of circle is perpendicular to tangent)
Hence, ∆OPQ is a right angles triangle
​$$(H)^2 = (P)^2 + (B)^2 \\\ \\(37)^2 = (P)^2 + (12)^2 \\\ \\(P)^2 = (37)^2 - (12)^2$$​​
P =35cm
Using Pythagoras triplets