A rectangular water tank of internal base 11 m $$\times$$​ 7 m contains water upto a height of 8 m. If the water in the rectangular tank is transferred to an empty cylindrical tank of radius 7 m, then the height of the water level in the cylindrical tank is (assume no overflow) ($$Use \pi = \frac{22}{7}$$​)

Correct option is A

Given:

Rectangular tank dimensions: Length = 11 m, Width = 7 m, Height of water = 8 m

Cylindrical tank radius = 7 m

π = $$\frac{22}{7}$$​​

Formula Used:

Volume of rectangular tank = Length × Width × Height

Volume of cylindrical tank = π × r² × h

Solution:

Volume of water = 11 × 7 × 8 = 616 cubic meters

Volume of water = $$\frac{22}{7} \times 7^2 \times h$$​ = 154h

Equating the volume of water transferred from the rectangular tank to the cylindrical tank:

616 = 154h

h = $$\frac{616}{154}$$​= 4 meters

The height of the water level in the cylindrical tank is 4 meters