Five solid cubes, each of volume 1,09,41,048 cm³, are joined end to end to form a cuboid. What is the lateral surface area (in cm²) of the cuboid?​

Correct option is A

Given:

Volume of one cube = 1,09,41,048 cm³

Five identical cubes are joined end-to-end to form a cuboid.

Formula Used:

Edge length of a cube = $$\sqrt[3]{\text{Volume}}$$​​

Lateral surface area of a cuboid = 2h(l + b)

Solution:

Edge length of one cube = $$\sqrt[3]{1\,0941\,048} = 222 \ \text{cm}$$​​

Dimensions of the cuboid;

Length (5 cubes in a row) = 5 × 222 = 1110 cm

Breadth & Height (same as cube edge) = 222 cm

Lateral surface area = 2 × 222 × (1110 + 222)

= 2 × 222 × 1332

= 5,91,408 cm²