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    A person travels from X to Y at a speed of 50 km/hr and returns from Y to X by increasing his speed by 50%. His average speed during the journey is:
    Question



    A person travels from X to Y at a speed of 50 km/hr and returns from Y to X by increasing his speed by 50%. His average speed during the journey is:

    A.

    62.5 km/hr

    B.

    60 km/hr

    C.

    62 km/hr

    D.

    64 km/hr

    Correct option is B

    Given:

    A person travels from X to Y at a speed of 50 km/hr and returns from Y to X by increasing his speed by 50%

    Formula Used:

    Average speed = 2S1S2S1+S2\frac{2S_1S_2}{S_1 + S_2}​​

    Here S1, Sare the speed

    Calculation:

    Speed at time of returning = 50 × 150% = 75 km/h

    Average speed = 2×50×7550+75=60km/hr\frac{2 \times 50 \times 75}{50 + 75} = 60 km/hr​​

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