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A person travels from X to Y at a speed of 50 km/hr and returns from Y to X by increasing his speed by 50%. His average speed during the journey is:
Question



A person travels from X to Y at a speed of 50 km/hr and returns from Y to X by increasing his speed by 50%. His average speed during the journey is:

A.

62.5 km/hr

B.

60 km/hr

C.

62 km/hr

D.

64 km/hr

Correct option is B

Given:

A person travels from X to Y at a speed of 50 km/hr and returns from Y to X by increasing his speed by 50%

Formula Used:

Average speed = 2S1S2S1+S2\frac{2S_1S_2}{S_1 + S_2}​​

Here S1, Sare the speed

Calculation:

Speed at time of returning = 50 × 150% = 75 km/h

Average speed = 2×50×7550+75=60km/hr\frac{2 \times 50 \times 75}{50 + 75} = 60 km/hr​​

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