A nucleus has an atomic number 64. Considering the nucleus as a liquid-drop, its radius will be close to

($$\text R_0$$​= 1.2 fm):

Correct option is C

​$$\textbf{Concept:} \\\bullet\ \text{The atomic nucleus is the } \textbf{small, dense core} \text{ of an atom where protons and neutrons are concentrated.} \\\bullet\ \text{The nuclear radius is estimated using the empirical formula:} \\R = R_0 \cdot A^{1/3} \\\text{Where:} \\\quad R_0 = 1.2\, \text{fm is the nuclear radius constant} \\\quad A \text{ is the atomic mass number} \\\\\textbf{Calculation:} \\\text{Given,} \\\text{Atomic mass number } A = 64 \\\text{Radius constant } R_0 = 1.2\, \text{fm} \\\text{Using the formula:} \\R = R_0 \cdot A^{1/3} \\R = 1.2 \times (64)^{1/3} \\R = 1.2 \times 4 = 4.8\, \text{fm}$$​​