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    Let N and N0\text N_0N0​​ be the number of radioactive nuclei in a sample at time t and at time t = 0, respectively. Then the ratio (NN0\fra
    Question

    Let N and N0\text N_0​ be the number of radioactive nuclei in a sample at time t and at time t = 0, respectively. Then the ratio (NN0\frac{\text N}{\text N_0}​) is equal to __________ where λ is the disintegration constant or decay constant.

    A.

    e(2λ)te^{-(2λ)t}​​

    B.

    e

    C.

    e(λ2)te^{-(\frac{λ}{2})t}​​

    D.

    e(λ)te^{-(λ)t}​​

    Correct option is D

    Radioactive Decay Formula:N=N0eλtWhere: N0 is the initial number of nuclei at t=0 N is the number of nuclei remaining at time t λ is the decay constantNow, rearranging to get the ratio NN0:NN0=eλt\textbf{Radioactive Decay Formula:} \\N = N_0 e^{-\lambda t} \\\\\text{Where:} \\\bullet\ N_0\ \text{is the initial number of nuclei at } t = 0 \\\bullet\ N\ \text{is the number of nuclei remaining at time } t \\\bullet\ \lambda\ \text{is the decay constant} \\\\\text{Now, rearranging to get the ratio } \frac{N}{N_0}: \\\frac{N}{N_0} = e^{-\lambda t}​​

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