Correct option is C
Given:
A is twice as old as B.
B is as old as C.
The sum of the ages of A, B, and C is 42 years.
Solution:
Let B's age be x.
Since A is twice as old as B, A = 2x.
Since B is as old as C, we have C = 3x.
According to the question, the sum of the ages of A, B, and C is 42:
A + B + C = 42
Substituting the values of A, B, and C:
2x + x + 3x = 42
6x = 42
x = 7
Now, substitute x = 7 to find the ages of A and B:
B = x = 7
A = 2x = 2×7 = 14
The sum of the ages of A and B is:
14 + 7 = 21
Thus, The sum of the ages of A and B is 21 years.
Alternate Method:
Let the age of C be 3 unit.
then, age of B = 1 unit, age of A = 2 unit
According to the question;
(2 + 1 + 3)unit = 42 year
6 unit = 42 year
1 unit = 7 year
thus, age of A = 2×7 = 14year
age of B = 7 year
Sum of age of A + B = 14 + 7 = 21 year
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