A few lead spheres of diameter 6 cm are dropped into a cylindrical beaker containing some water such that they are fully submerged. If the diameter of the beaker is 9 cm and the water level has risen y 32 cm, find the number of lead spheres dropped into the beaker.
Given:
The radius of the sphere is 3 cm
Radius & height of cylinder are 4.5 cm & 32cm
Formula used:
The volume of sphere = 4/3πr³
The volume of cylinder = πr²h
Solution:
The volume of sphere inserted = volume of water risen in beaker
Radius of sphere = 6/2= 3 cm
Radius of cylinder = 9/2 = 4.5
So,
(4/3)π × (3)³ × Number of sphere = π (4.5) × (4.5) × 32
=> Number of sphere = 18
Hence, option (a) is the correct answer.
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