A cylindrical rod has an outer curved surface area of 4500 cm$$^2$$​. If the length of the rod is 62 cm, then the outer radius (in cm) of the rod, correct to two places of decimal, is:
​$$Take \pi = \frac {22}{7}$$​

Correct option is A

Given:

Outer Curved Surface Area (A) = 4500 cm²

Length of the rod (h) = 62 cm

Formula Used:

Curved Surface Area of Cylinder = 2πrh
Where,
r = radius of the base
h = height (length of the rod)

Solution:

​$$4500 = 2 \times \left(\frac{22}{7}\right) \times r \times 62  \\ \ \\\implies r = \frac{4500}{2 \times \left(\frac{22}{7}\right) \times 62}  \\ \ \\\implies r = \frac{4500}{\frac{2732}{7}}   \\ \ \\\implies r = \frac{4500 \times 7}{2732}   \\ \ \\\implies r = \frac{31500}{2732}  \\ \ \\\implies r \approx 11.55 \, \text{cm}$$​​

Thus, the outer radius of the rod is 11.55 cm.