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A channel is said to be the most economical section when, it gives maximum discharge for a given area and slope. What is the relation between hydrauli
Question

A channel is said to be the most economical section when, it gives maximum discharge for a given area and slope. What is the relation between hydraulic radius and depth for the most economical trapezoidal section?

A.

Hydraulic radius = 2 times depth

B.

Hydraulic radius = 1.5 times depth

C.

Hydraulic radius = depth/2

D.

Hydraulic radius = depth/3

Correct option is C

Conditions for the most economical or efficient section:
 From Chezy’s and Mannings equation that the velocity of flow will be maximum when hydraulic radius R will be maximum for factors like the slope of bed, and surface roughness being constant.
 Hydraulic radius is maximum if the wetted perimeter is minimum.
Most economical rectangular section:
 Width of the channel is twice the depth of flow (B = 2y).
 Hydraulic radius is half of the depth of flow. ( R= y/ 2)
Most economical trapezoidal section:
 Half of the top width must be equal to the sloping side.
 The hydraulic radius must be half the depth of water.
Most economical triangular section:
 The side slope has to be inclined at 45∘.

​Most economical circular section:
 The depth of flow(y) = 0.81D. (for maximum velocity)
 The hydraulic radius(R) for maximum velocity is 0.3 D
 The depth of flow(y) = 0. 95D. (for maximum discharge)
Where D = Diameter of channel

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