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    A certain number of apples, when attempted to be distributed to three groups in the ratio 3:4:5, fall short by one. If distributed in the ratio 4:5:6
    Question

    A certain number of apples, when attempted to be distributed to three groups in the ratio 3:4:5, fall short by one. If distributed in the ratio 4:5:6 two apples would be left undistributed. Which one of the following is a possible number of apples?

    A.

    35

    B.

    47

    C.

    59

    D.

    62

    Correct option is B

    Given:

    In ratio 3:4:5 → apples fall short by 1
    In ratio 4:5:6 → 2 apples are extra

    Concept:

    ​We will convert the statements into mathematical expressions and then solve it.

    Solution:

    ​According to the first statement, if the total number of apples is n, then

    3x + 4x + 5x - 1 = n
    12x - 1 = n

    According to the second statement,

    4y + 5y + 6y + 2 = n
    15y + 2 = n

    Comparing both the equations, we get:
    12x - 1 = 15y + 2
    => 12x - 15y = 3
    => 4x - 5y = 1

    Solving this, we find that x = 4 and y = 3 satisfies the equation.

    So, number of apples = 12x - 1 = 12*4 - 1 = 47

    Hence, number of apples is 47.

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