A can complete a piece of work in 18 days and B can complete it in 22 days. If they work on alternate days, starting with B on the first day, then in how many days will the work be finished?
Given:
A completes the work in 18 days =>
B completes the work in 22 days =>
They work on alternate days starting with B
Solution:
Total work = LCM of 18 and 22 = 198
Efficiency of A = unit/day
Efficiency of B = unit/day
2 days work = ( 9 +11) = 20 unit
18 days work = 180 unit
19 days work = 180 + 9 = 189 unit
Remaining ( 198 - 189 = 9) work done by A = days
Total time = 19 + = days
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