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A can complete 25% of a task in 10 days. B can complete 40% of the task in 40 days and C can complete 13\frac{1}{3}31​​ of the task in 13 days. W
Question

A can complete 25% of a task in 10 days. B can complete 40% of the task in 40 days and C can complete 13\frac{1}{3}​ of the task in 13 days. Who among them has the fastest speed to complete the same task?

A.

All have the same speed

B.

C

C.

A

D.

B

Correct option is B

Given:

A completes 25% of the task in 10 days

B completes 40% of the task in 40 days

C completes 13\frac{1}{3}​ of the task in 13 days

Solution:

A completes 25% of the task in 10 days

To complete 100% of the task

TimeA=100×10 days25=40 days\text{Time}_A = \frac{100\times10 \text{ days}}{25} = 40 \text{ days}​​

B completes 40% of the task in 40 days

To complete 100% of the task

TimeB=40 days×10040=100 days\text{Time}_B = \frac{40 \text{ days}\times100}{40} = 100 \text{ days}​​

C completes  13\frac{1}{3}​  of the task in 13 days

To complete 100% of the task

TimeC=13 days13=39 days\text{Time}_C = \frac{13 \text{ days}}{\frac{1}{3}} = 39 \text{ days}

TimeA=40 days\text{Time}_A = 40 \text{ days}​​

TimeB=100 days\text{Time}_B = 100 \text{ days}​​

TimeC=39 days\text{Time}_C = 39 \text{ days}​​

C takes the least time to complete the task

C has the fastest speed to complete the task 

Thus Option (b) is correct 

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