A camp has provisions for 60 persons for 18 days. In how many days will the same provisions finish off if the strength of the camp is increased to 90 persons?

Correct option is A

Given:

Provision for 60 person last = 18days

Formula Used:

Let number of men, total days be M,D.

Then, $$M_{1}\times D_{1}= M_{2}\times D_{2}$$​​

Solution:

If 60 persons consume provision in 18 days then 90 persons will consume provision in x days

​$$M_{1}\times D_{1}= M_{2}\times D_{2}$$​​

​$$60\times 18= 90 \times x$$​​

​$$x= \frac{ 60 \times 18 }{90}$$​​

​$$=12days$$​​