Given:
A, B and C can complete a task in 10, 15 and 18 days
Solution:
First we take LCM of 10,15,18
LCM =90
so total work is 90 units
A work done in 1 day = =9 units
B work done in 1 day = =6 units
Similarly ,C work done in 1 day = =5units
so A,B,C work done in one 1 day = 9+6+5=20 units
total work = 90units
work done by A,B,C together in = days
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