A, B and C can complete a piece of work in 12 days, 24 days and 36 days, respectively. A starts working alone on the first day and then A is assisted by B on the second day and C on the third day, respectively. This pattern is repeated till the work gets completed. In how many days does the work will be over?
Total Work = LCM of 12 , 24, and 36= 72 unit
Efficiency of A, B and C = 6 , 3 and 2 unit per day respectively.
On first day, A's work = 6 unit
On second day, work done by A and B = 6+ 3 = 9 unit
On third day, work done by A and C = 6+ 2= 8 unit
So, in total 3 days 23 unit of work has been completed.
Hence, In 9 days 69 unit of work will complete.
3 unit of remaining work has to be done by A = 3/6 = day
Total time to complete the whole work = 9+1/2 = days
English
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