Correct option is E
Let the total work be 120 unit (LCM of 24, 15 and 20)
So, the efficiency of A + B = 5 unit/day
The efficiency of B + C = 8 unit/day
The efficiency of A + C = 6 unit/day
The efficiency of A + B + C = (5+8+6)/2 = 19/2 unit/day
So, the efficiency of B =19/2 -6 = 7/2 unit/day
Let the time taken by B to complete the remaining work be x days.
ATQ,