A 6-digit number has digits as consecutive natural numbers. The number is always divisible by

Correct option is D

Concept Used:
Any 6-digit number formed by a consecutive natural number is always divisible by 3 because the sum of digits of any such number is divisible by 3.
Solution:
Let 1^st consecutive no. be = a
∴ Sum of all nos. => 6a + 15
This sum should be divisible by 3,
=> 3(2a +5) → is always divisible by 3.
Alternate Solution:
Take 123456, 234567, 345678, and 456789, as a number, the sum of its digit is always divisible by 3.