5 apples, 6 oranges and 7 bananas cost 250, while 6 apples, 4 oranges and 2 bananas cost 180. The cost (in) of 4 oranges and 8 bananas is

Correct option is C

Solution:

Let:

• Cost of 1 apple = A
• Cost of 1 orange = O
• Cost of 1 banana = B

We are given:

1. 5A + 6O + 7B = 250
2. 6A + 4O + 2B = 180

We are asked to find:
Cost of 4 oranges and 8 bananas = 4O + 8B

Step 1: Eliminate A from the two equations.

Multiply:

• First equation by 6 →
  30A + 36O + 42B = 1500
• Second equation by 5 →
  30A + 20O + 10B = 900

Now subtract the second from the first:

(30A + 36O + 42B) − (30A + 20O + 10B)
= 16O + 32B = 600

Now divide the entire equation by 4:

4O + 8B = 150

Final Answer: (C) 150