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Zakir travels from City A to City B. If Zakir drives his car at 3/8 th of his normal speed, then he reaches City B 10 minutes late. Find the time (in
Question

Zakir travels from City A to City B. If Zakir drives his car at 3/8 th of his normal speed, then he reaches City B 10 minutes late. Find the time (in minutes) that Zakir would have taken to travel from City A to City B if he drove at his normal speed.

A.

5

B.

6

C.

14

D.

10

Correct option is B

Given
New speed = 3/8 of normal speed
Late by = 10 minutes
Formula Used
Speed and Time are inversely proportional (when distance is constant).
Solution
Let normal speed be S and normal time be T.
New speed = 38S \frac{3}{8} S​​
Since Speed ∝1Time \frac{1}{Time}​, New time = 83T \frac{8}{3} T​​
Difference in time = New time - Normal time
​83T−T=10 53T=10 \frac{8}{3} T - T = 10 \\\ \\\frac{5}{3} T = 10 \\\ \\​​
T = 10×3510 × \frac{3}{5}​​
T = 6 minutes
Final Answer
So the correct answer is (b)

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