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A car covers three different segments of a journey: it travels 40 km at a speed of 60 km/hr, then 50 km at a speed of 50 km/hr and finally 60 km at a
Question

A car covers three different segments of a journey: it travels 40 km at a speed of 60 km/hr, then 50 km at a speed of 50 km/hr and finally 60 km at a speed of 40 km/hr. What is the car's average speed (rounded off to one decimal place) for the entire trip?

A.

47.4 km/hr

B.

48.3 km/hr

C.

52.9 km/hr

D.

50.3 km/hr

Correct option is A

Given:
Segment 1: Distance = 40 km, Speed = 60 km/hr
Segment 2: Distance = 50 km, Speed = 50 km/hr
Segment 3: Distance = 60 km, Speed = 40 km/hr
Formula Used:
Time = DistanceSpeed\frac{Distance}{Speed}​​
Average Speed =  Total DistanceTotal Time\frac{Total\ Distance}{Total \ Time}​​
Solution:
Total Distance = 40 + 50 + 60 = 150 km
Time for Segment 1 = 4060=23\frac{40}{60} = \frac{2}{3}​ hours

Time for Segment 2 = 5050\frac{50}{50}​ = 1 hour

Time for Segment 3 = 6040=32\frac{60}{40} = \frac{3}{2}​ hours

Total Time = 23+1+32\frac{2}{3} + 1 + \frac{3}{2}​​

Total Time = 46+66+96=196 \frac{4}{6} + \frac{6}{6} + \frac{9}{6} = \frac{19}{6}​ hours

Average Speed =150196= \frac{150}{\frac{19}{6}}​​

Average Speed =150×619=90019= \frac{150 × 6}{19} = \frac{900}{19}​​
Average Speed = 47.368... km/hr
Rounding off to one decimal place gives 47.4 km/hr.
Final Answer
So the correct answer is (a)

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