Correct option is C
✅ (c) 150:
· Let the maximum marks be MMM.
· Passing marks = 40% of MMM = 0.40M0.40M0.40M.
· Y scores 20 marks and fails by 40 marks, so he needed 20+40=6020 + 40 = 6020+40=60 marks to pass.
· Thus, 0.40M=600.40M = 600.40M=60
· Solving for MMM, M=600.40=150M = \frac{60}{0.40} = 150M=0.4060=150.
· Therefore, the maximum marks are 150.
❌ (a) 100: If max marks were 100, passing marks = 40, but Y’s failure by 40 marks is not possible here. ❌ (b) 200: Passing marks would be 80, but that contradicts the given failure difference. ❌ (d) 250: Passing marks = 100, which doesn’t fit the failure condition described.