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If the radius of the base of a right circular cylinder is decreased by 17% and its height is increased by 138%, then what is the percentage increase (
Question

If the radius of the base of a right circular cylinder is decreased by 17% and its height is increased by 138%, then what is the percentage increase (rounded off to the closest integer) in its volume?

A.

64%

B.

55%

C.

75%

D.

61%

Correct option is A

Given
Radius decrease = 17%
Height increase = 138%
Formula Used
Volume of cylinder = π×r2×h π × r^2 × h​​
Percentage Change = (Final VolumeInitial Volume \frac{\text{Final Volume}}{\text{Initial Volume}} ​- 1 ) × 100
Solution
Let original radius be r and original height be h.
Initial Volume (V1)=π×r2×h(V_1) = π × r^2 × h​​
New radius = r × (1 - 0.17) = 0.83r
New height = h × (1 + 1.38) = 2.38h
New Volume (V2)=π×(0.83r)2×(2.38h)(V_2) = π × (0.83r)^2 × (2.38h)​​

Increase in volume = 1.639582 - 1 = 0.639582
Percentage increase = 0.639582 × 100 = 63.9582%
Rounded off to the closest integer = 64%

Final Answer
So the correct answer is (a)

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