Without repeating the digits 0, 3 and 5, how many different three digit numbers can be formed using these three digits?

Correct option is D

Given:
We are asked to form 3-digit numbers using the digits 0, 3, and 5,
without repeating any digit.

Concept:
A 3-digit number cannot start with 0.

We are to use all 3 digits exactly once in each number.

So we are calculating the number of 3-digit permutations of 0, 3, and 5 excluding those starting with 0.

Solution:
Total permutations of 3 digits without repetition = 3! = 6
List of all such numbers using 0, 3, 5:

035 (invalid – starts with 0)

053 (invalid – starts with 0)

305

350

503

530

Only 4 valid three-digit numbers.

Final Answer: 4