Which one of the following figures correctly shows the variation of electric potential V (in units of ) and electric field E (in units of ) with distance r for a point charge Q?

Correct option is D

Correct answer is D
Concept:
The variation of electric potential {V) and electric field {E) for a point charge Q with distance r can be expressed as:
Electric potential, V = (Q/4πε0) × (1/r)
Electric field, E = (Q/4πε0) × (1/r2)
Here:
ε0 is the permittivity of free space.
r is the distance from the point charge Q.Q
Explanation:
The electric potential {V) decreases inversely with r, while the electric field {E) decreases inversely with r2.
As r increases:
V => decreases as 1/r.
E => decreases faster as 1/r2.
Therefore, the graph showing the correct variation of V and E with r will have:
V showing a slower decay compared to E.
E decaying more sharply as r increases.