Which of the following statements is/are NOT true regarding the work done by a constant force acting on a body?
(i) The work done by the force can never be negative.
(ii) If the direction of the force and displacement of the body is same, the work done will be positive.
(iii) The S.l. unit of work done is Pascal.

Correct option is D

The correct answer is (d) Both (i) and (iii)

Explanation:
• Work (W) in basic physics is rigorously quantitatively defined mathematically as the dot product of applied force (F) and measured displacement (s) directly in the exact direction of the force, mathematically formally expressed as $W = Fs \cos\theta$.
• Statement (i) is factually NOT true primarily because calculated work can most definitely be negative; this specifically precisely happens when the applied force and the resulting displacement actively act in perfectly opposite directions (where $\theta = 180^\circ$), such as the resisting work routinely done by kinetic friction.
• Statement (ii) is fundamentally true clearly because when the applied force and the displacement perfectly align in the exact identical same direction, $\cos(0^\circ) = 1$, automatically resulting in a strictly fully positive value for mechanical work.
• Statement (iii) is factually NOT true mostly because the accepted standard S.I. unit of physical work is naturally the Joule (J), whereas the heavily used Pascal (Pa) is strictly the standard S.I. unit strictly designated exclusively for measuring fluid or mechanical pressure.
• Therefore, examining all carefully, both statements (i) and (iii) clearly represent the fundamentally completely incorrect statements.

Information Booster:
• Technically work done precisely mathematically evaluates to exactly zero when the continuously applied force acts perfectly perpendicular to the object's displacement (e.g., a walking porter physically carrying a highly heavy load horizontally balanced strictly on his head).
• Exactly one Joule is scientifically precisely defined universally as the exact amount of mechanical work done purely when a steady force of exactly 1 Newton successfully displaces any given object by exactly 1 meter perfectly along its specific line of action.

Additional Knowledge:
Only (ii) (Option a)
• This careless option grossly incorrectly identifies the only completely true statement clearly as the ostensibly false one.

Only (i) (Option b)
• While given statement (i) is indeed demonstrably completely false, this poor option completely blindly ignores the perfectly equivalently totally false statement (iii).

Both (ii) and (iii) (Option c)
• This badly flawed option extremely incorrectly strangely includes statement (ii), which clearly is a perfectly valid and completely scientifically true basic statement strictly regarding standard positive work.

So the correct answer is (d)