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    Which of the following statement is correct? I. If amount = Rs. 26500, time = 5 years, and rate of interest = 16.5 percent per annum, then the princ
    Question

    Which of the following statement is correct?
    I. If amount = Rs. 26500, time = 5 years, and rate of interest = 16.5 percent per annum, then the principal is Rs. 14000 on simple interest.
    II. If principal = Rs. 22000, amount = Rs. 39160 and time = 6 years, then at simple interest rate of interest is 13 percent per annum.



    A.

    Neither I nor II

    B.

    Only I

    C.

    Only II

    D.

    Both I and II

    Correct option is C

    Given:
    I. If amount = Rs. 26500, time = 5 years, and rate of interest = 16.5 percent per annum.
    II. If principal = Rs. 22000, amount = Rs. 39160 and time = 6 years.

    Formula Used:
    Simple Interest (SI)=P×R×T100\text{Simple Interest (SI)} = \frac{P \times R \times T}{100}​​
    Amount = Principal  + Simple Interest
    Solution:
    Statement I:
    26500=P+P×R×T10026500=P+P×16.5×510026500=P(1+16.5×5100)26500=P(1+82.5100)26500=P(182.5100)P=26500×100182.5P14520.55PRs 14000\begin{align*}& 26500 = P + \frac{P \times R \times T}{100} \\& 26500 = P + \frac{P \times 16.5 \times 5}{100} \\& 26500 = P \left(1 + \frac{16.5 \times 5}{100}\right) \\& 26500 = P \left(1 + \frac{82.5}{100}\right) \\& 26500 = P \left(\frac{182.5}{100}\right) \\ & P = 26500 \times \frac{100}{182.5} \\& P \approx 14520.55 \\ & P \ne \text{Rs }14000\end{align*}​​
    Statement II:
    39160=22000+22000×6×R10017160=22000×6×R100R=1339160 = 22000 + \frac{22000 \times 6 \times R}{100} \\17160 = \frac{22000 \times 6 \times R}{100} \\R = 13​​

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