Which of the following reactions would undergo precipitation?

Correct option is A

​The correct answer is (a) Pb (N0₃)₂ + KI

Explanation: When lead nitrate Pb (N0₃)₂ reacts with potassium iodide KI, it produces a yellow precipitate of lead iodide and potassium nitrate.

Information Booster:

• The reaction is a double displacement and precipitation reaction.
• Here are some properties of the products of this reaction:
• Potassium nitrate: Dissolves in water
• Lead(II) iodide: Only moderately soluble in water, so most of it precipitates out as a yellow solid
• Lead(II) nitrate is an inorganic molecule that is often a colorless crystal or white powder. It is water soluble, but it should be handled with caution to avoid inhalation, ingestion, or skin contact.​