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Which Boolean law is represented by the equation A.(B+C)=(A.B)+(A.C) ?
Question

Which Boolean law is represented by the equation A.(B+C)=(A.B)+(A.C) ?

A.

Idempotent Law

B.

Commutative Law

C.

Distributive Law

D.

Associative Law

Correct option is C

The Boolean expression:A(B+C)=(AB)+(AC)is a direct application of the Distributive Law, where multiplication () distributes over addition (+) — similar to algebra.\text{The Boolean expression:} \\[6pt]A \cdot (B + C) = (A \cdot B) + (A \cdot C) \\[6pt]\text{is a direct application of the \textbf{Distributive Law}, where multiplication (}\cdot\text{) distributes over addition (+) --- similar to algebra.}​​

NameAND FormOR FormIdentity Law1A=A0+A=ANull Law0A=01+A=1Idempotent LawAA=AA+A=AInverse LawAA=0A+A=1Commutative LawAB=BAA+B=B+AAssociative Law(AB)C=A(BC)(A+B)+C=A+(B+C)Distributive LawA+BC=(A+B)(A+C)A(B+C)=AB+ACAbsorption LawA(A+B)=AA+AB=ADe Morgan’s Law(AB)=A+B(A+B)=AB\begin{array}{|c|c|c|}\hline\textbf{Name} & \textbf{AND Form} & \textbf{OR Form} \\\hline\text{Identity Law} & 1 \cdot A = A & 0 + A = A \\\hline\text{Null Law} & 0 \cdot A = 0 & 1 + A = 1 \\\hline\text{Idempotent Law} & A \cdot A = A & A + A = A \\\hline\text{Inverse Law} & A A' = 0 & A + A' = 1 \\\hline\text{Commutative Law} & A B = B A & A + B = B + A \\\hline\text{Associative Law} & (A B) C = A (B C) & (A + B) + C = A + (B + C) \\\hline\text{Distributive Law} & A + B C = (A + B)(A + C) & A (B + C) = A B + A C \\\hline\text{Absorption Law} & A (A + B) = A & A + A B = A \\\hline\text{De Morgan’s Law} & (A B)' = A' + B' & (A + B)' = A' B' \\\hline\end{array}​​

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