When x = 1 then y is directly proportional to x + 3 and y = 8. When z = 6 then x is inversely proportional to z and x = 2. Find the relation between y and z.

Correct option is D

​$$y \propto (x+3) \\y = k (x+3)\\y=8 \,and \, x=1\\ 8 = k(1+3)\\k = 2\\Similarly,\\ z \propto \frac{1}{x}\\ z = \frac{m}{x}\\When z= 6\,and \,x= 2\\m = 12\\From \, equation \,1 \,and \,2\\y = 2(x+3) and z= 12/x\\y = 2 (\frac{12}{z}+ 3)\\yz = 24 + 6z \\z (y-6)= 24$$