What will be the ratio of the numbers which have a difference of 56 and the first number is 2/9 of the second?

Correct option is C

Given
Difference between numbers = 56
First number = $$\frac{2}{9}$$​ of Second number

Solution
Let the second number be y.
Then the first number x = $$\frac{2}{9}y.$$​​
Given difference: y - x = 56
​$$y - \frac{2}{9}y = 56$$​​

​$$\frac{7}{9}y = 56\\\ \\y = \frac{56 \times 9}{7} = 8 \times 9 = 72\\\ \\x = \frac{2}{9} \times 72 = 16\\\ \\$$​​
Ratio of numbers (x : y) = 16 : 72
Divide by 8:

2 : 9

Final Answer
So the correct answer is (c)