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    When viewed from the top of a tower of height 100 metres, the angle of elevation of a boat is 30 degrees. The boat moved "x" metres towards the tower
    Question

    When viewed from the top of a tower of height 100 metres, the angle of elevation of a boat is 30 degrees. The boat moved "x" metres towards the tower and the angle of elevation changed to 5 degrees. Find the value of "x"?

    A.

    100

    B.

    50

    C.

    100(31)100(\sqrt{3} - 1)​​

    D.

    100(3+1)100(\sqrt{3} + 1)​​

    Correct option is C

    Given:
    Height of the tower (h) = 100 m
    Initial angle of elevation = 30°
    Final angle of elevation = 45°
    Boat moves x metres closer to the tower

    Use tan θ = height / distance
    Solution:
    Let initial horizontal distance from the boat to the base of the tower be D
    Then:
    tan(30°) = 100 / D
    tan(45°) = 100 / (D − x)

    We will solve both equations to find x
    From first triangle:
    tan(30°) = 1/√3 => D = 100√3

    From second triangle:
    tan(45°) = 1 => D − x = 100
    => x = D − 100 = 100√3 − 100

    Take 100 common:
    => x = 100(√3 − 1)

    Final Answer:
    (C) 100(31)100(\sqrt{3} - 1)​​

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