The angle of elevation of the top of a tower from a point on the ground, which is 48 m away from the foot of the tower is 30°. Find the height of the tower.

Correct option is D

Given:
Horizontal distance = 48m,
Angle of elevation $$= 30^\circ$$​​
Solution:

Assume, height of tower be h.

​$$\tan 30^\circ=\frac{h}{48}$$​​
​$$\frac{1}{\sqrt{3}}=\frac{h}{48}$$​​

h=$$\frac{48}{\sqrt{3}}=16\sqrt{3}\ \text{m}$$​​
​$$\text{Height of the tower }=16\sqrt{3}$$​ m