when the shadow of a pole of 10 m height is 10$$\sqrt3$$​m, the angular elevation of the Sun is:

Correct option is A

Given:

Height of the pole = 10 m
Length of the shadow = 10$$\sqrt{3}$$​m

Formula Used:

The angular elevation of the Sun, \theta, is given by the tangent function:
​$$\tan \theta = \frac{\text{Height of the pole}}{\text{Length of the shadow}}$$​​

Solution:

Substitute the given values into the formula:
​$$\tan \theta = \frac{10}{10\sqrt{3}} = \frac{1}{\sqrt{3}}$$​​

The angle whose tangent is$$\frac{1}{\sqrt{3}}= 30^\circ$$​.

Thus, the angular elevation of the Sun is $$30^\circ$$​.