When the digits of a two-digit number are reversed, the value of the number is increased by 45. The sum of the digits is 11. What is the original number?

Correct option is C

Let the number be 10x+y
As per the question
x + y = 11…………(1)
and
(10y +x) - (10x+y) = 45
9 (y – x) = 45
y – x = 5 …………..(2)
from equation (1) and (2)
x = 3 and y = 8
So, the number be 38