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When the digits of a two-digit number are reversed, the value of the number is increased by 45. The sum of the digits is 11. What is the original numb
Question

When the digits of a two-digit number are reversed, the value of the number is increased by 45. The sum of the digits is 11. What is the original number?

A.

83

B.

65

C.

38

D.

24

Correct option is C


Let the number be 10x+y
As per the question
x + y = 11…………(1)
and
(10y +x) - (10x+y) = 45
9 (y – x) = 45
y – x = 5 …………..(2)
from equation (1) and (2)
x = 3 and y = 8
So, the number be 38

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