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    When a female Drosophila having white eye trait (X-linked) is crossed with a male having dominant red eye trait, what would be the possibility of thes
    Question

    When a female Drosophila having white eye trait (X-linked) is crossed with a male having dominant red eye trait, what would be the possibility of these traits in the offspring of F1 generation?

    A.

    All the F1 males will be red eyed and females would be white eyed.

    B.

    All the F1 males will be white eyed and females would be red eyed.

    C.

    All the offspring will be white eyed.

    D.

    All the offspring will be red eyed.

    Correct option is B

    Correct Answer: (b)
    Explanation:
    White eye in Drosophila is an X-linked recessive trait. Cross: female (XᵂXᵂ) × male (X⁺Y). Daughters (XᵂX⁺) are phenotypically red-eyed (carrier), sons (XᵂY) are white-eyed. Thus all F1 males white, females red.
    Information Booster:
    X-linked recessive traits show different patterns in males (hemizygous) and females (homo/heterozygous).
    Males inherit their X chromosome from the mother and Y from the father.
    In this cross the mother supplies the mutant X to all sons.
    Females receive X⁺ from father and Xᵂ from mother → phenotypically dominant (red).
    Reciprocal crosses can give different F1 sex patterns for X-linked traits.
    Additional Information (Incorrect Options):
    (a) Reversed sexes — incorrect given allele distribution.
    (c)/(d) All offspring same phenotype would only occur if parental alleles produced that outcome; here sexes differ due to X-linkage.

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