What would be the highest value of X in the given equation?

5X1 + 6Y7 + 3Z3 = 1471

Correct option is C

Given:

The equation is 5X1 + 6Y7 + 3Z3 = 1471, where X, Y, and Z are variables.

Solution:
We interpret the numbers in the equation as follows:

5X1 = 500 + 10X + 1

6Y7 = 600 + 10Y + 7

3Z3 = 300 + 10Z + 3

So, the equation becomes:

(500 + 10X + 1) + (600 + 10Y + 7) + (300 + 10Z + 3) = 1471

1411 + 10X + 10Y + 10Z = 1471

10X + 10Y + 10Z = 1471 - 1411

10X + 10Y + 10Z = 60

X + Y + Z = 6
The sum of X, Y, and Z is 6. To maximize X, we should minimize Y and Z. The smallest value for both Y and Z is 0, so:

X = 6 - 0 - 0 = 6

Thus, the highest value of X is 6.