What will be the area (in cm$$^2$$​) of a semicircle whose perimeter is 72 cm? (Take $$\pi = \frac{22}{7}$$​)

Correct option is A

Given:

Perimeter of semicircle = 72cm

Formula Used:

Area of a semicircle = $$\frac{\pi r^2}{2}$$​​

Perimeter of a semicircle =$$\pi r +2r$$​​

Solution:

Perimeter =$$\pi r +2r = 72$$​​

​$$r( \pi + 2 ) = 72$$​​

​$$r( \frac{22}{7} + 2 ) = 72$$​​

​$$r( \frac{22+14}{7}) = 72$$​​

​$$r= 72 \times \frac{7}{36}$$​​

r = 14cm 

Area of Semicircle:

Area =$$\frac{\pi (14)^2}{2}$$​​

=$$\frac{22}{7} \times 14 \times 7$$​​

= $$308cm^2$$​​