What number must be subtracted from both the numerator and denominator of the fraction $$\frac{15}{19}$$​ so as to make it $$\frac{3}{4}$$ ?

Correct option is D

Given:

Original fraction =$$\frac{15}{19}$$​​
Required fraction after subtraction =$$\frac{3}{4}$$​​

Solution:
Let the number to be subtracted from both numerator and denominator be x.

$$\frac{15 - x}{19 - x} = \frac{3}{4}$$​

60 - 4x = 57 - 3x

60 - 57 = 4x - 3x

3 = x

Required number = 3