Find the sum of digits of the greatest number of five digits which is a perfect square.

Correct option is B

Given:
Number constraints: 5 digits, largest possible, perfect square.
Formula Used:
Long division method for square roots.
Solution:
The largest 5-digit number generally is 99999.
To find the largest perfect square, we find the square root of 99999.
​$$\sqrt{99999} \approx 316.22$$​​
The largest integer whose square is less than or equal to 99999 is 316.
Calculate the square of 316:
​$$316^2 = 316 × 316 = 99856.$$​​
So, 99856 is the greatest 5-digit perfect square.
Sum of the digits = 9 + 9 + 8 + 5 + 6 = 37.
Final Answer
So the correct answer is (b)