A fraction is such that if the double of the numerator and the triple of denominator is changed by +10% and -30% respectively, then we get 11% of 16/21. The fraction is

Correct option is B

Given:
Numerator (x) doubled and increased by 10%.
Denominator (y) tripled and decreased by 30%.
Resulting fraction = 11% of $$\frac{16}{21}.$$​​
Formula Used:
New Numerator = 2x × 1.10
New Denominator = 3y × 0.70
Solution:
Let the original fraction be $$\frac{x}{y}.$$​​
The new numerator is 2x + 10% of 2x = 2.2x.
The new denominator is 3y - 30% of 3y = 3y - 0.9y = 2.1y.
The given result is 11% of $$\frac{16}{21} = \frac{11}{100} × \frac{16}{21}$$​​
Set up the equation:
​$$\frac{2.2x}{2.1y} = \frac{11 × 16}{100 × 21} \\ \ \\\frac{22x}{21y} = \frac{176}{2100}\\ \ \\\frac{x}{y} = \frac{176 × 21}{2100 × 22}\\ \ \\\frac{x}{y} = \frac{8}{100} = \frac{2}{25}$$​​
Final Answer
So the correct answer is (b)