What number must be subtracted from both the denominator and numerator of the fraction $$\frac{42}{45}​$$​ so that it becomes $$\frac56$$​ ?

Correct option is D

Given:

Original fraction = $$\frac{42}{45}$$​​
Required fraction after subtracting a number $$= \frac{5}{6}$$​​

Solution:
Let the number to be subtracted be x. Then,

​$$\frac{42 - x}{45 - x} = \frac{5}{6}$$​​

6(42 - x) = 5(45 - x)

252 - 6x = 225 - 5x

252 - 225 = 6x - 5x

x = 27