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    What is the value of  514+612+734−8125\frac{1}{4} +6\frac{1}{2}+7\frac{3}{4}-8\frac{1}{2}541​+621​+743​−821​​ ?
    Question

    What is the value of  514+612+7348125\frac{1}{4} +6\frac{1}{2}+7\frac{3}{4}-8\frac{1}{2}​ ?

    A.

    11

    B.

    8

    C.

    9

    D.

    10

    Correct option is A

    Given: 
    514+612+7348125\frac{1}{4} +6\frac{1}{2}+7\frac{3}{4}-8\frac{1}{2} 
    Concept Used: 
    BODMAS rule:
    Operation preference wiseSymbol Brackets[],,()Orders, of ²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline \text{ Brackets} &[],{}, () \\ \hline \text{Orders, of }& ² (power), √ (root) , of \\ \hline \text{Division} & ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\ \hline \end{array}    
    Solution: 
    =514+612+734812 =214+132+314172 =52442 =5284 =444 =11= 5\frac{1}{4} +6\frac{1}{2}+7\frac{3}{4}-8\frac{1}{2} \\ \ \\ = \frac{21}{4} + \frac{13}{2}+\frac{31}{4}-\frac{17}2 \\ \ \\ = \frac{52}{4} - \frac{4}{2} \\ \ \\ = \frac{52 - 8}{4} \\ \ \\ = \frac{44}{4} \\ \ \\ = \bf 11​​​​

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