Correct option is AGiven: 514+612+734−8125\frac{1}{4} +6\frac{1}{2}+7\frac{3}{4}-8\frac{1}{2}541+621+743−821 Concept Used: BODMAS rule:Operation preference wiseSymbol Brackets[],,()Orders, of ²(power),√(root),ofDivision÷Multiplication×Addition+Subtraction−\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline \text{ Brackets} &[],{}, () \\ \hline \text{Orders, of }& ² (power), √ (root) , of \\ \hline \text{Division} & ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\ \hline \end{array} Operation preference wise BracketsOrders, of DivisionMultiplicationAdditionSubtractionSymbol[],,()²(power),√(root),of÷×+− Solution: =514+612+734−812 =214+132+314−172 =524−42 =52−84 =444 =11= 5\frac{1}{4} +6\frac{1}{2}+7\frac{3}{4}-8\frac{1}{2} \\ \ \\ = \frac{21}{4} + \frac{13}{2}+\frac{31}{4}-\frac{17}2 \\ \ \\ = \frac{52}{4} - \frac{4}{2} \\ \ \\ = \frac{52 - 8}{4} \\ \ \\ = \frac{44}{4} \\ \ \\ = \bf 11=541+621+743−821 =421+213+431−217 =452−24 =452−8 =444 =11