What is the median of the following data?

78, 56, 22, 34, 45, 54, 39, 68, 54, 84

Correct option is C

Given:

78, 56, 22, 34, 45, 54, 39, 68, 54, 84

Formula Used: 

For ever number terms;

Median = $$\frac{\text{Value at position} \frac{n}{2}+\text{Value at position} \frac{n}{2}+1}{2}$$​​​

Solution:

The given data is:
78,56,22,34,45,54,39,68,54,84
Arranged in ascending order:
22,34,39,45,54,54,56,68,78,8

In this case, n = 10 (even)

Median = $$\frac{[(\text {5th term}) + (\text {6th term})]}{ 2}$$​

The 5th value is 54, and the 6th value is also 54.​​​

​Median = ​​$$\frac{54+54}{2}$$​

​​Median = $$\frac{108}{2}$$​​

​​Median = 54

Thus, option (c) is correct.