What is the ASA congruence rule of triangles, where A and S represents angle and side of triangle respectively?

If the areas of two similar triangles are in the ratio 121 : 225, what would be the ratio of the corresponding sides?

In two triangle ABC and DEF, if $$\bar{AB} = \bar{EF} , \bar{BC} = \bar{DF} \space and \space \bar{CA} = \bar{DE}, \space then:$$​​

The lengths of corresponding sides of two similar triangles are in the ratio 5 : 6. The areas of these triangles are in the ratio:

In $$\triangle ABC$$​,$$\overline{PQ} \parallel \overline{AB}$$​. P and Q are on BC and CA respectively. If CQ : QA = 1 : 3 and CP = 4, then what is the value of BC?

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D, E, F are midpoints of the sides BC, CA, AB of a ∆ABC. If area of ∆ABC is 20 cm²​ , then find area of the trapezium FBCE.