What is the area of the region swept by the minute hand 6 cm long, of a wall cock, in an interval of 5 minutes?

Correct option is D

Given:

Length of minute hand = 6 cm
Time interval = 5 minutes

Formula Used:
Area of sector$$= \frac{\theta}{360} \times \pi r^2$$​​
where θ is the angle in degrees and r is the radius.

Solution:

Angle swept in 5 minutes = $$\frac{5}{60} \times 360^\circ = 30^\circ$$​​

Area $$= \frac{30}{360} \times \pi \times (6)^2 = \frac{1}{12} \times \pi \times 36 = 3\times \frac {22}7 \ \text{cm}^2 \approx 9.43 \ \text{cm}^2$$​​