What is the angle between the clock hands at 11 : 20?

Given: The clock hands at 11 : 20

Formula Used: $$\begin{vmatrix} 30H - \frac {11}{2}M \end{vmatrix}$$

= $$\begin{vmatrix} 30\times 11 - \frac {11}{2}\times 20 \end{vmatrix}$$

= $$\begin{vmatrix} 330 - 110\end{vmatrix}$$

= $$\begin{vmatrix}220 \end{vmatrix}$$

Since the maximum possible angle on a clock is 180°, we take the smaller angle by subtracting from 360°:​​

= 360 - 220

= 140°

Thus, correct option is (d).