Given:
Vipin can do a piece of work in 2 days; Vaibhav can do the same work in 3 days and Chirag can do the same work in 6 days.
Formula Used:
Time = Total Work / Efficiency
Solution:
Let total work be = LCM of 2, 3 and 6= 6 units
Efficiency of Vipin is 3 units/day
Efficiency of Vaibhav is 2 units/day
Efficiency of Chirag is 1 unit/day
Together they do the work in = 6/(3+2+1) = 1 day
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100 Questions
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