Two masses of 1 kg and 2 kg were dropped from a height of 3.2 metres. Their respective velocities just before touching the ground will be: (Assume acceleration due to gravity g = 10 m/s²)

Correct option is D

Correct Answer:(d) 8 m/s for both
Explanation:
The velocity of an object just before it touches the ground can be found using the equation of motion under constant acceleration (in this case, due to gravity). The formula is:
v=\sqrt{2ghv}
where:
· v is the final velocity,
· g is the acceleration due to gravity (10 m/s²),
· h is the height from which the object is dropped (3.2 m).
Now, substituting the values:
v=\sqrt{2×10×3.2}=\sqrt{64}=8 m/s
Thus, both masses (1 kg and 2 kg) will have the same velocity just before touching the ground because the final velocity is independent of the mass, given that both masses fall under the same gravitational acceleration.