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Two computers A and B are configured as follows: A has IP address 203.197.2.53 and subnet mask 255.255.128.0, B has IP address 203.197.75.201 and subn
Question

Two computers A and B are configured as follows: A has IP address 203.197.2.53 and subnet mask 255.255.128.0, B has IP address 203.197.75.201 and subnet mask 255.255.192.0. What one of the following statement is true?

A.

A and B both assume they are on the same network

B.

B assumes, A is on same network, A assumes B is on different network

C.

A assumes, B is on same network, but B assumes, A is on a different network

D.

A and B both assume they are on different network

Correct option is C

We are given:
Computer A

  • IP Address: 203.197.2.53
  • Subnet Mask: 255.255.128.0

Computer B

  • IP Address: 203.197.75.201
  • Subnet Mask: 255.255.192.0

We must determine whether each computer considers the other to be on the same network or a different network.
Step 1: Understand the Subnet Masks
A’s Subnet Mask​​
255.255.128.
Binary:
11111111.11111111.10000000.00000000
This corresponds to:
/17
Meaning:

  • First 17 bits = Network portion
  • Remaining bits = Host portion

B’s Subnet Mask
255.255.192.0
Binary:
11111111.11111111.11000000.00000000
This corresponds to:
/18
Meaning:

  • First 18 bits = Network portion

Step 2: Check A’s View of B
A uses subnet mask:
255.255.128.0
So, A checks whether B belongs to the same /17 network.
A’s Network Address
IP:
203.197.2.53
Third octet = 2
With /17:

  • Network ranges are:
    • 0–127
    • 128–255

Since 2 lies in:
0 − 127
A’s network is:
203.197.0.0/17
B’s IP
203.197.75.201
Third octet = 75
75 also lies in:
0 − 127
Thus, B also belongs to:
203.197.0.0/17
Therefore:
A assumes B is on the same network\boxed{\text{A assumes B is on the same network}}​​
Step 3: Check B’s View of A
B uses subnet mask:
255.255.192.0
i.e. /18.
With /18:

  • Third octet ranges become:
    • 0–63
    • 64–127
    • 128–191
    • 192–255

B’s Network
B’s IP:
203.197.75.201
Third octet = 75
75 lies in:
64 − 127
So, B belongs to:
203.197.64.0/18
A’s IP
203.197.2.53
Third octet = 2
2 lies in:
0 − 63
So, A belongs to:
203.197.0.0/18
Thus, A and B are in different /18 networks.
Therefore:
B assumes A is on a different network\boxed{\text{B assumes A is on a different network}}​​
Final Conclusion

  • A thinks B is on the same network.
  • B thinks A is on a different network.

Correct Answer
(c) A assumes B is on same network, but B assumes A is on a different network\boxed{\text{(c) A assumes B is on same network, but B assumes A is on a different network}} ​​​
Information Booster
1. Subnetting Rule
Two hosts are considered on the same network if:
(IP AND Subnet Mask)
gives the same network address.
2. CIDR Notation

Subnet Mask

CIDR

255.255.128.0

/17

255.255.192.0

/18

3. Important Concept
Communication assumptions may become asymmetric when hosts use different subnet masks. One host may think the destination is local while the other thinks it is remote.

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